((-20x^-3y^0)/8z^-1)^-3

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Solution for ((-20x^-3y^0)/8z^-1)^-3 equation: 


D( x )

((-20*y^0*x^-3)/8)*z^-1 = 0

x = 0

((-20*y^0*x^-3)/8)*z^-1 = 0

((-20*y^0*x^-3)/8)*z^-1 = 0

((-20*x^-3)/8)*z^-1 = 0

-5/2*x^-3*z^-1 = 0 // : -5/2*z^-1

x^-3 = 0

x naleu017Cy do O

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(((-20*y^0*x^-3)/8)*z^-1)^-3 = 0

(((-20*x^-3)/8)*z^-1)^-3 = 0

-8/125*x^9*z^3 = 0 // : -8/125*z^3

x^9 = 0

x = 0

x in { 0} 

x belongs to the empty set

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